When I reached the acid-base calculation section of my freshman
chemistry course, I struggled with it significantly.
After what seemed like hours of research, I found a series of
AB tutorials on You Tube by the channel, “WoodsonChem.”
Once I figured out the basics of working the problems through these tutorials, I noticed a repeated pattern, an observation that saved me
a lot of time while taking the section exam, and got me a good grade; I eventually "boiled down" the whole set of equations into one step...
The one-step method for finding pH:
Given a ka value, and a molarity for a weak acid, the
following applies:
- -log (sqrt[(ka)(M)])=pH
- And for good measure, 14-pH=pOH
I hope that this will be useful.
Resources:
Woodson Chem. Retrieved from, https://www.youtube.com/watch?v=QQYmE0ZISq0
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